16z^2-72z+81=0

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Solution for 16z^2-72z+81=0 equation: 



16z^2-72z+81=0

a = 16; b = -72; c = +81;
Δ = b2-4ac
Δ = -722-4·16·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{72}{32}=2+1/4$

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